Conductance and Unit Conversions (Electrochemistry) MCQs for CSIR UGC NET, GATE - Download PDF

Conductance MCQ Questions
for CSIR UGC NET & GATE

Electrochemistry
Topic wise Assignment-1

QUIZ              PDF

Q1. The strength of a solution is 6 kg/L, unit conversion to g/ml and kg/m³ will be
(a) 60, 600
(b) 6, 6000
(c) 600, 60
(d) 6000, 6

Q2. The specific conductance of a solution is 0.176 S cm^-1. If cell constant is 0.255 cm^-1, The conductance in 'S' of the solution should be:

[NET June 2017]

(a) 1.449
(b) 0.690
(c) 0.045
(d) 0.431

Q3. The equivalent conductance at infinite dilution of a strong electrolyte Λ^o_eq can be obtained from the plot of

[NET Dec 2017]

(a) Λ vs C
(b) Λ vs (C)^1/2
(c) Λ vs C²
(d) Λ vs 1/C

Q4. If the specific conductance of an electrolytic solution is 0.2 S cm^-1 and cell constant is 0.25 cm^-1, the conductance of solution should be:

[NET Dec 2017]

(a) 1.25 S
(b) 1.0 S
(c) 0.8 S
(d) 2.0 S

Q5. A 0.05 M KOH solution has a resistance of 31.6 Ω in a conductivity cell of cell constant 0.316 cm^-1 at 298K. Calculate the molar conductivity.
(a) 200 S m² mol^-1
(b) 200 S cm² mol^-1
(c) 20 S m² mol^-1
(d) 20 S cm² mol^-1

Q6. When a certain conductivity cell was filled with 0.02 M KCl solution which has a specific conductance of 0.2 S m^-1 and resistance of 80 Ω at 298K. When this solution is replaced by 0.0025 M K₂SO₄, it has a resistance of 320 Ω. Calculate the
(i) Cell constant, (ii) Conductivity of K₂SO₄, (iii) Molar conductivity of K₂SO₄
(a) 16 m^-1, 0.05 S m^-1, 0.02 S m² mol^-1
(b) 16 cm^-1, 0.05 S cm^-1, 0.02 S cm² mol^-1
(c) 16 m^-1, 0.05 S cm^-1, 0.02 S m² mol^-1
(d) 16 cm^-1, 0.05 S m^-1, 0.02 S cm² mol^-1

Q7. The specific conductance of a 0.01 M solution of CH₃COOH was found to be 0.016 S m^-1 at 298 K. Calculate the degree of dissociation of acetic acid given that Λ^o_m = 0.04 S m² mol^-1
(a) 0.4
(b) 0.004
(c) 0.04
(d) 0.0004

Q8. The molar conductivity of a 0.05 M MgCl₂ is 194.2 S cm² mol^-1 at 298 K. A cell with electrodes that are 1.50 cm² in surface area and 0.5 cm apart is filled with the MgCl₂ solution. How much current will flow when potential difference between two electrodes is 5.0 V.
(a) 0.25 A
(b) 0.015 A
(c) 0.15 mA
(d) 0.15 A

Q9. The conductivity of 0.1 M NaOH solution is 0.0221 S cm^-1. When an equal volume of 0.1 M HCl is added, the conductivity decreases to 0.0056 S cm^-1. Calculate Λ_m(NaCl)
(a) 112 S m² mol^-1
(b) 112 S cm² mol^-1
(c) 0.112 S cm² mol^-1
(d) None

Q10. The molar conductivity of a 0.01 M weak acid (HX) at 298 K, measured in a cell of cell constant 0.4 cm^-1 is 64.4 S cm² mol^-1. The limiting molar conductivities at infinite dilution of H⁺ and X^- are 350 and 410 S cm² mol^-1. The pKa of HX at 298 K is

[GATE 2018]

(a) 4.2
(b) 4.9
(c) 5.7
(d) 6.1

Answer Key

Q1-b, Q2-b, Q3-b, Q4-c, Q5-b, Q6-a, Q7-c, Q8-d, Q9-b, Q10-a

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