Nernst Equation (Electrochemistry) MCQs for CSIR NET GATE - ChemContent

In this article, ChemContent has brought to you an MCQ quiz containing questions from Nernst equation topic from Electrochemistry. 

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Quiz                        PDF

Q1. If the ratio of composition of oxidized and reduced species in electrochemical cell, is given as [O]/[R]=e², the correct potential difference E-E° will be

[NET June 2011]

      (a)  2RT/nF
(b)  -2RT/nF
(c)  RT/nF
(d)  -RT/nF

Q2. The standard electrode potentials (E°) of Fe³⁺/Fe²⁺ and Fe²⁺/Fe electrodes are +0.77 V and -0.44 V respectively at 300 K. The E° of Fe³⁺/Fe electrode at the same temperature is

[NET Dec 2011]

    (a)  1.21 V
(b)  0.33 V
(c)  -0.11 V
(d)  -0.04 V

Q3. Which one of the following conductometric titrations will show a linear increase of the conductance with volume of the titrant added up to the break point and an almost constant conductance afterwards.

[NET Dec 2011]

    (a)  A strong acid with a strong base
(b)  A strong acid with a weak base
(c)  A weak acid with a strong base
(d)  A weak acid with a weak base

Q4. The correct value of E°, of a half cell in the following graph of E vs log m (m=molality) is:

[NET June 2012]

    (a)  CC'/AC'
(b)  AB'
(c)  BB'
(d) CC'

Q5. The Daniel cell is

[NET Dec 2012]

    (a)  Pt_I(s) | Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s) | Pt_II(s)
(b)  Pt_I(s) | Zn(s) | Zn²⁺(aq) || Ag⁺(aq) | Ag(s) | Pt_II(s)
(c) Pt_I(s) | Fe(s) | Fe²⁺(aq) || Cu²⁺(aq) | Cu(s) | Pt_II(s)
(d) Pt_I(s) | H₂(g) | H₂SO₄(aq) || Cu²⁺(aq) | Cu(s) | Pt_II(s)

Q6. The correct representation of the variation of molar conductivity (y-axis) with surfactant concentration (x-axis) is [CMC=Critical Micelle Concentration].

[NET Dec 2012]

Q7. The equilibrium constant for an electrochemical reaction,

2 Fe³⁺ + Sn²⁺   ⇌  2 Fe²⁺ + Sn⁴⁺

is [E°(Fe³⁺/Fe²⁺) = 0.75 V, E°(Sn⁴⁺/Sn²⁺) = 0.15 V, (2.303RT/F) = 0.06 V]

[NET Dec 2012]

    (a)  10¹⁰
(b)  10²⁰
(c)  10³⁰
(d)  10⁴⁰

Q8. Which is correct Nernst equation for redox reaction O + ne^- ⇌ R?

[NET June 2013]

Q9. The cell voltage of Daniel cell [Zn | ZnSO₄(aq) || CuSO₄(aq) | Cu] is 1.07 V. If reduced potential of Cu²⁺ | Cu is 0.34 V, the reduction potential of Zn²⁺ | Zn is

[NET Dec 2013]

    (a)  0.141 V
(b)  -1.41 V
(c)  0.73 V
(d)  -0.73 V

Q10. Consider the cell:

Zn | Zn²⁺ (a=0.01) || Fe²⁺ (a=0.001), Fe³⁺ (a=0.01) | Pt

E_cell = 1.71 V at 25°C for the above cell. The equilibrium constant for the reaction:

Zn + 2 Fe³⁺  ⇌   Zn²⁺ + 2 Fe²⁺

At 25°C would be close to

[NET Dec 2013]

    (a)  10²⁷
(b)  10⁵⁴
(c)  10⁸¹
(d) 10⁴⁰

Answer Key

Q1.a Q2.d Q3.d Q4.c Q5.a Q6.b Q7.b Q8.b Q9.d Q10.b

Detailed Solutions [Click Here]

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