VSEPR Theory MCQ Questions
for CSIR UGC NET & GATE
Chemical Bonding
Topic wise Assignment-4
Q1. The correct shape of [TeF5]- ion on the bases of VSEPR theory is
(b) Square pyramidal
(c) Pentagonal planer
(d) See-Saw
Q2. The number of triangular faces in square antiprism, icosahedron and tricapped triagonal prism (capped on square faces) respectively are
(b) 8, 20, 12
(c) 10, 12, 14
(d) 10, 12, 12
Q3. The number of 3c-2e bonds present in Al(BH4)3 is
(b) 3
(c) 6
(d) 0
Q4. The oxidation state of gold in the following complex is
(a) 0
(b) 1
(c) 2
(d) 3
Q5. The compound (SiH3)3N is expected to be
(b) Planer and less basic than (CH3)3N
(c) Pyramidal and less basic than (CH3)3N
(d) Planer and more basic than (CH3)3N
Q6. The hybrid orbitals used by bromine atom in BrF3 are
(b) sp3
(c) sp3d
(d) sp3d2
Q7. The species which has a square planer structure is
(b) FeCl4-
(c) SF4
(d) XeF4
Q8. The structures of O3 and N3- are
(b) both linear
(c) both bent
(d) bent and linear respectively
Q9. The Xenon compounds that are isostructural with IBr2- and BrO3- respectively are
(b) Bent XeF2 and Pyramidal XeO3
(c) Bent XeF2 and planer XeO3
(d) Linear XeF2 and Tetrahedral XeO3
Q10. [XeO6]4- is octahedral whereas XeF6 is a disordered one because
(b) Xe has a lone pair in XeF6
(c) XeF6 is neutral whereas [XeO6]4- is anionic
(d) Xe-F bond has more ionic character
Q11. The pair of compounds having same hybridization for the central atom is
(a) XeF4 and [SiF6]2-
(b) [NiCl4]2- and [PtCl4]2-
(c) Ni(CO)4 and XeO2F2
(d) [Co(NH3)6]3+ and [Co(H2O)6]3+
Q12. The geometry around central atom in ClF4+
(a) square planer
(b) square pyramidal
(c) octahedral
(d) trigonal bipyramidal
Q13. According to VSEPR theory, the shape of [XeOF5]- is
(b) trigonal bipyramidal
(c) square pyramidal
(d) pentagonal pyramidal
Q14. According to VSEPR theory, the shapes of [SF2Cl]+ and [S2O4]2- should be
(b) both trigonal planer
(c) trigonal pyramidal for [S2O4]2- and trigonal planer for [SF2Cl]+
(d) both trigonal pyramidal
Q15. The order of polarity of NH3, NF3 and BF3 is
(b) BF3 < NF3 < NH3
(c) BF3 < NH3 < NF3
(d) NF3 < BF3 < NH3
Q16. The compound with planer geometry is
(b) NPh3
(c) NF3
(d) N(SiH3)3
Ans Key
1.b 2.a 3.c 4.c 5.b 6.c 7.d 8.d 9.a 10.b 11.a,d 12.d 13.d 14.d 15.b 16.dTopicwise MCQ Chapterwise MCQ